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(68/(1+2^x))-x=0
Domain of the equation: (1+2^x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2^x)!=-1
x!=-1/1
x!=-1
x∈R
-1x+(68/(1+2^x))=0
We multiply all the terms by the denominator
-1x*(1+2^x))+(68=0
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